-0.125x^2+4.7x-22.09=0

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Solution for -0.125x^2+4.7x-22.09=0 equation: 



-0.125x^2+4.7x-22.09=0

a = -0.125; b = 4.7; c = -22.09;
Δ = b2-4ac
Δ = 4.72-4·(-0.125)·(-22.09)
Δ = 11.045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.7)-\sqrt{11.045}}{2*-0.125}=\frac{-4.7-\sqrt{11.045}}{-0.25}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.7)+\sqrt{11.045}}{2*-0.125}=\frac{-4.7+\sqrt{11.045}}{-0.25}
$

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